Base | Representation |
---|---|
bin | 110011110010010100… |
… | …0110111100101011001 |
3 | 101122001102102110222122 |
4 | 1213210220313211121 |
5 | 3310224241213311 |
6 | 123031134231025 |
7 | 11014614155642 |
oct | 1474450674531 |
9 | 348042373878 |
10 | 111210101081 |
11 | 43189225a52 |
12 | 19678055475 |
13 | a644119c51 |
14 | 554dbc26c9 |
15 | 2d5d47b0db |
hex | 19e4a37959 |
111210101081 has 2 divisors, whose sum is σ = 111210101082. Its totient is φ = 111210101080.
The previous prime is 111210100919. The next prime is 111210101089. The reversal of 111210101081 is 180101012111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 104351611225 + 6858489856 = 323035^2 + 82816^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111210101081 is a prime.
It is a super-2 number, since 2×1112101010812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (111210101089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55605050540 + 55605050541.
It is an arithmetic number, because the mean of its divisors is an integer number (55605050541).
Almost surely, 2111210101081 is an apocalyptic number.
It is an amenable number.
111210101081 is a deficient number, since it is larger than the sum of its proper divisors (1).
111210101081 is an equidigital number, since it uses as much as digits as its factorization.
111210101081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 17.
Adding to 111210101081 its reverse (180101012111), we get a palindrome (291311113192).
The spelling of 111210101081 in words is "one hundred eleven billion, two hundred ten million, one hundred one thousand, eighty-one".
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