Base | Representation |
---|---|
bin | 1010000111010100111111… |
… | …1011000101111010011111 |
3 | 1110101011021101121121001011 |
4 | 2201311033323011322133 |
5 | 2424201312333021002 |
6 | 35352531054000051 |
7 | 2225316011450344 |
oct | 241651773057237 |
9 | 43334241547034 |
10 | 11121011220127 |
11 | 35a8437a00746 |
12 | 12b73b01a6027 |
13 | 628925c76613 |
14 | 2a638cd0a7cb |
15 | 14443a30a8d7 |
hex | a1d4fec5e9f |
11121011220127 has 2 divisors, whose sum is σ = 11121011220128. Its totient is φ = 11121011220126.
The previous prime is 11121011220091. The next prime is 11121011220211. The reversal of 11121011220127 is 72102211012111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11121011220127 - 231 = 11118863736479 is a prime.
It is a super-2 number, since 2×111210112201272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11121011220098 and 11121011220107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11121011220227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560505610063 + 5560505610064.
It is an arithmetic number, because the mean of its divisors is an integer number (5560505610064).
Almost surely, 211121011220127 is an apocalyptic number.
11121011220127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121011220127 is an equidigital number, since it uses as much as digits as its factorization.
11121011220127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 11121011220127 its reverse (72102211012111), we get a palindrome (83223222232238).
The spelling of 11121011220127 in words is "eleven trillion, one hundred twenty-one billion, eleven million, two hundred twenty thousand, one hundred twenty-seven".
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