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1112110101313 is a prime number
BaseRepresentation
bin10000001011101110111…
…011010111001101000001
310221022112212100122200121
4100023232323113031001
5121210100141220223
62210521335020241
7143230060614241
oct20135673271501
93838485318617
101112110101313
11399709183392
1215b64b50a681
1380b439ac2b3
143bb7d985b21
151ddddc1e15d
hex102eeed7341

1112110101313 has 2 divisors, whose sum is σ = 1112110101314. Its totient is φ = 1112110101312.

The previous prime is 1112110101287. The next prime is 1112110101329. The reversal of 1112110101313 is 3131010112111.

It is an a-pointer prime, because the next prime (1112110101329) can be obtained adding 1112110101313 to its sum of digits (16).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 650100338944 + 462009762369 = 806288^2 + 679713^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1112110101313 is a prime.

It is a super-2 number, since 2×11121101013132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1112110401313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556055050656 + 556055050657.

It is an arithmetic number, because the mean of its divisors is an integer number (556055050657).

Almost surely, 21112110101313 is an apocalyptic number.

It is an amenable number.

1112110101313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112110101313 is an equidigital number, since it uses as much as digits as its factorization.

1112110101313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 1112110101313 its reverse (3131010112111), we get a palindrome (4243120213424).

The spelling of 1112110101313 in words is "one trillion, one hundred twelve billion, one hundred ten million, one hundred one thousand, three hundred thirteen".