Base | Representation |
---|---|
bin | 1010000111010101010101… |
… | …0010000010100101011011 |
3 | 1110101011111122210002001211 |
4 | 2201311111102002211123 |
5 | 2424202003341400013 |
6 | 35352544024523551 |
7 | 2225321152553524 |
oct | 241652522024533 |
9 | 43334448702054 |
10 | 11121101121883 |
11 | 35a8483725215 |
12 | 12b74163205b7 |
13 | 62893b79291c |
14 | 2a639ac2d84b |
15 | 14444316823d |
hex | a1d5548295b |
11121101121883 has 2 divisors, whose sum is σ = 11121101121884. Its totient is φ = 11121101121882.
The previous prime is 11121101121829. The next prime is 11121101121937. The reversal of 11121101121883 is 38812110112111.
It is a balanced prime because it is at equal distance from previous prime (11121101121829) and next prime (11121101121937).
It is a cyclic number.
It is not a de Polignac number, because 11121101121883 - 213 = 11121101113691 is a prime.
It is not a weakly prime, because it can be changed into another prime (11121101121803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560550560941 + 5560550560942.
It is an arithmetic number, because the mean of its divisors is an integer number (5560550560942).
Almost surely, 211121101121883 is an apocalyptic number.
11121101121883 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121101121883 is an equidigital number, since it uses as much as digits as its factorization.
11121101121883 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 31.
Adding to 11121101121883 its reverse (38812110112111), we get a palindrome (49933211233994).
The spelling of 11121101121883 in words is "eleven trillion, one hundred twenty-one billion, one hundred one million, one hundred twenty-one thousand, eight hundred eighty-three".
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