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11121101142013 is a prime number
BaseRepresentation
bin1010000111010101010101…
…0010000111011111111101
31110101011111122211002200101
42201311111102013133331
52424202003343021023
635352544025201101
72225321152666312
oct241652522073775
943334448732611
1011121101142013
1135a8483739355
1212b7416330191
1362893b79bb35
142a639ac36d09
1514444316e1ad
hexa1d554877fd

11121101142013 has 2 divisors, whose sum is σ = 11121101142014. Its totient is φ = 11121101142012.

The previous prime is 11121101142001. The next prime is 11121101142037. The reversal of 11121101142013 is 31024110112111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7248813139044 + 3872288002969 = 2692362^2 + 1967813^2 .

It is a cyclic number.

It is not a de Polignac number, because 11121101142013 - 241 = 8922077886461 is a prime.

It is a super-2 number, since 2×111211011420132 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11121101142043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560550571006 + 5560550571007.

It is an arithmetic number, because the mean of its divisors is an integer number (5560550571007).

Almost surely, 211121101142013 is an apocalyptic number.

It is an amenable number.

11121101142013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11121101142013 is an equidigital number, since it uses as much as digits as its factorization.

11121101142013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 11121101142013 its reverse (31024110112111), we get a palindrome (42145211254124).

The spelling of 11121101142013 in words is "eleven trillion, one hundred twenty-one billion, one hundred one million, one hundred forty-two thousand, thirteen".