Base | Representation |
---|---|
bin | 10000001011101110111… |
… | …110110010100101011111 |
3 | 10221022112221001022022201 |
4 | 100023232332302211133 |
5 | 121210100403444103 |
6 | 2210521410152331 |
7 | 143230101346111 |
oct | 20135676624537 |
9 | 3838487038281 |
10 | 1112110999903 |
11 | 399709737522 |
12 | 15b64b8826a7 |
13 | 80b43c352c7 |
14 | 3bb7db3b3b1 |
15 | 1ddddd4a51d |
hex | 102eefb295f |
1112110999903 has 4 divisors (see below), whose sum is σ = 1112113152648. Its totient is φ = 1112108847160.
The previous prime is 1112110999897. The next prime is 1112110999927. The reversal of 1112110999903 is 3099990112111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1112110999903 - 217 = 1112110868831 is a prime.
It is a super-2 number, since 2×11121109999032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1112110991903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214848 + ... + 1506778.
It is an arithmetic number, because the mean of its divisors is an integer number (278028288162).
Almost surely, 21112110999903 is an apocalyptic number.
1112110999903 is a deficient number, since it is larger than the sum of its proper divisors (2152745).
1112110999903 is an equidigital number, since it uses as much as digits as its factorization.
1112110999903 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2152744.
The product of its (nonzero) digits is 39366, while the sum is 46.
The spelling of 1112110999903 in words is "one trillion, one hundred twelve billion, one hundred ten million, nine hundred ninety-nine thousand, nine hundred three".
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