Base | Representation |
---|---|
bin | 11001010010010101100000… |
… | …101110111110010101011101 |
3 | 112120202200120111221220021202 |
4 | 121102111200232332111131 |
5 | 104034041030021401023 |
6 | 1032305420341405245 |
7 | 32265513325264532 |
oct | 3122254056762535 |
9 | 476680514856252 |
10 | 111211211122013 |
11 | 32487456454182 |
12 | 10581589709825 |
13 | 4a09231463272 |
14 | 1d669193b4d89 |
15 | ccccd3792128 |
hex | 652560bbe55d |
111211211122013 has 2 divisors, whose sum is σ = 111211211122014. Its totient is φ = 111211211122012.
The previous prime is 111211211121973. The next prime is 111211211122139. The reversal of 111211211122013 is 310221112112111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 76084762584964 + 35126448537049 = 8722658^2 + 5926757^2 .
It is a cyclic number.
It is not a de Polignac number, because 111211211122013 - 226 = 111211144013149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111211211121013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55605605561006 + 55605605561007.
It is an arithmetic number, because the mean of its divisors is an integer number (55605605561007).
Almost surely, 2111211211122013 is an apocalyptic number.
It is an amenable number.
111211211122013 is a deficient number, since it is larger than the sum of its proper divisors (1).
111211211122013 is an equidigital number, since it uses as much as digits as its factorization.
111211211122013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 20.
Adding to 111211211122013 its reverse (310221112112111), we get a palindrome (421432323234124).
The spelling of 111211211122013 in words is "one hundred eleven trillion, two hundred eleven billion, two hundred eleven million, one hundred twenty-two thousand, thirteen".
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