Base | Representation |
---|---|
bin | 10000001011101111000… |
… | …110111010101000010011 |
3 | 10221022120002001112021022 |
4 | 100023233012322220103 |
5 | 121210101430130003 |
6 | 2210521523550055 |
7 | 143230125430241 |
oct | 20135706725023 |
9 | 3838502045238 |
10 | 1112113130003 |
11 | 39970a961937 |
12 | 15b65052b32b |
13 | 80b444cca15 |
14 | 3bb80133791 |
15 | 1ddde11b738 |
hex | 102ef1baa13 |
1112113130003 has 2 divisors, whose sum is σ = 1112113130004. Its totient is φ = 1112113130002.
The previous prime is 1112113129979. The next prime is 1112113130053. The reversal of 1112113130003 is 3000313112111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1112113130003 - 234 = 1094933260819 is a prime.
It is a super-2 number, since 2×11121131300032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1112113130053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556056565001 + 556056565002.
It is an arithmetic number, because the mean of its divisors is an integer number (556056565002).
Almost surely, 21112113130003 is an apocalyptic number.
1112113130003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112113130003 is an equidigital number, since it uses as much as digits as its factorization.
1112113130003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1112113130003 its reverse (3000313112111), we get a palindrome (4112426242114).
The spelling of 1112113130003 in words is "one trillion, one hundred twelve billion, one hundred thirteen million, one hundred thirty thousand, three".
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