Base | Representation |
---|---|
bin | 10000001011101111000… |
… | …111010001000111011111 |
3 | 10221022120002020012121201 |
4 | 100023233013101013133 |
5 | 121210101441101421 |
6 | 2210521525540331 |
7 | 143230126262623 |
oct | 20135707210737 |
9 | 3838502205551 |
10 | 1112113222111 |
11 | 39970aa15061 |
12 | 15b6505746a7 |
13 | 80b44532918 |
14 | 3bb80159183 |
15 | 1ddde138b91 |
hex | 102ef1d11df |
1112113222111 has 2 divisors, whose sum is σ = 1112113222112. Its totient is φ = 1112113222110.
The previous prime is 1112113222091. The next prime is 1112113222159. The reversal of 1112113222111 is 1112223112111.
It is a m-pointer prime, because the next prime (1112113222159) can be obtained adding 1112113222111 to its product of digits (48).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1112113222111 - 235 = 1077753483743 is a prime.
It is a super-2 number, since 2×11121132221112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1112116222111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556056611055 + 556056611056.
It is an arithmetic number, because the mean of its divisors is an integer number (556056611056).
Almost surely, 21112113222111 is an apocalyptic number.
1112113222111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112113222111 is an equidigital number, since it uses as much as digits as its factorization.
1112113222111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 48, while the sum is 19.
Adding to 1112113222111 its reverse (1112223112111), we get a palindrome (2224336334222).
The spelling of 1112113222111 in words is "one trillion, one hundred twelve billion, one hundred thirteen million, two hundred twenty-two thousand, one hundred eleven".
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