Base | Representation |
---|---|
bin | 1010000111010101101101… |
… | …0100001000000101001111 |
3 | 1110101011202201020002020001 |
4 | 2201311123110020011033 |
5 | 2424202210244110413 |
6 | 35353002042105131 |
7 | 2225323522045642 |
oct | 241653324100517 |
9 | 43334681202201 |
10 | 11121202331983 |
11 | 35a8525872927 |
12 | 12b74441ab1a7 |
13 | 62895673b163 |
14 | 2a63aa457a59 |
15 | 14444beab4dd |
hex | a1d5b50814f |
11121202331983 has 2 divisors, whose sum is σ = 11121202331984. Its totient is φ = 11121202331982.
The previous prime is 11121202331959. The next prime is 11121202331989. The reversal of 11121202331983 is 38913320212111.
It is a strong prime.
It is an emirp because it is prime and its reverse (38913320212111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11121202331983 - 241 = 8922179076431 is a prime.
It is a super-2 number, since 2×111212023319832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11121202331989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560601165991 + 5560601165992.
It is an arithmetic number, because the mean of its divisors is an integer number (5560601165992).
Almost surely, 211121202331983 is an apocalyptic number.
11121202331983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121202331983 is an equidigital number, since it uses as much as digits as its factorization.
11121202331983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 37.
The spelling of 11121202331983 in words is "eleven trillion, one hundred twenty-one billion, two hundred two million, three hundred thirty-one thousand, nine hundred eighty-three".
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