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111212131423241 is a prime number
BaseRepresentation
bin11001010010010110010111…
…100101101001010000001001
3112120202202221122200001020102
4121102112113211221100021
5104034044421121020431
61032310051534535145
732265545201565512
oct3122262745512011
9476682848601212
10111212131423241
1132487888992102
12105817a59674b5
134a0934a0171c4
141d669a56d7a09
15cccd3947ddcb
hex652597969409

111212131423241 has 2 divisors, whose sum is σ = 111212131423242. Its totient is φ = 111212131423240.

The previous prime is 111212131423213. The next prime is 111212131423277. The reversal of 111212131423241 is 142324131212111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103291447297600 + 7920684125641 = 10163240^2 + 2814371^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111212131423241 is a prime.

It is a super-3 number, since 3×1112121314232413 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (111212131423201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55606065711620 + 55606065711621.

It is an arithmetic number, because the mean of its divisors is an integer number (55606065711621).

Almost surely, 2111212131423241 is an apocalyptic number.

It is an amenable number.

111212131423241 is a deficient number, since it is larger than the sum of its proper divisors (1).

111212131423241 is an equidigital number, since it uses as much as digits as its factorization.

111212131423241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2304, while the sum is 29.

Adding to 111212131423241 its reverse (142324131212111), we get a palindrome (253536262635352).

The spelling of 111212131423241 in words is "one hundred eleven trillion, two hundred twelve billion, one hundred thirty-one million, four hundred twenty-three thousand, two hundred forty-one".