111212131423277 has 2 divisors, whose sum is σ = 111212131423278. Its totient is φ = 111212131423276.

The previous prime is 111212131423241. The next prime is 111212131423279. The reversal of 111212131423277 is 772324131212111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97665565342921 + 13546566080356 = 9882589^2 + 3680566^2 .

It is an emirp because it is prime and its reverse (772324131212111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111212131423277 - 2⁶ = 111212131423213 is a prime.

Together with 111212131423279, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 111212131423277.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111212131423279) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55606065711638 + 55606065711639.

It is an arithmetic number, because the mean of its divisors is an integer number (55606065711639).

Almost surely, 2^{111212131423277} is an apocalyptic number.

It is an amenable number.

111212131423277 is a deficient number, since it is larger than the sum of its proper divisors (1).

111212131423277 is an equidigital number, since it uses as much as digits as its factorization.

111212131423277 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 28224, while the sum is 38.

Adding to 111212131423277 its reverse (772324131212111), we get a palindrome (883536262635388).

The spelling of 111212131423277 in words is "one hundred eleven trillion, two hundred twelve billion, one hundred thirty-one million, four hundred twenty-three thousand, two hundred seventy-seven".