Base | Representation |
---|---|
bin | 1010000111010101110100… |
… | …1001111011001011111101 |
3 | 1110101011211212022221212012 |
4 | 2201311131021323023331 |
5 | 2424202241200242112 |
6 | 35353005104021005 |
7 | 2225324345401415 |
oct | 241653511731375 |
9 | 43334755287765 |
10 | 11121233212157 |
11 | 35a8541244632 |
12 | 12b7452601765 |
13 | 62895cc60953 |
14 | 2a63b05b5645 |
15 | 14444ea5b022 |
hex | a1d5d27b2fd |
11121233212157 has 2 divisors, whose sum is σ = 11121233212158. Its totient is φ = 11121233212156.
The previous prime is 11121233212091. The next prime is 11121233212171. The reversal of 11121233212157 is 75121233212111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6029941892836 + 5091291319321 = 2455594^2 + 2256389^2 .
It is a cyclic number.
It is not a de Polignac number, because 11121233212157 - 238 = 10846355305213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11121233212057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560616606078 + 5560616606079.
It is an arithmetic number, because the mean of its divisors is an integer number (5560616606079).
Almost surely, 211121233212157 is an apocalyptic number.
It is an amenable number.
11121233212157 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121233212157 is an equidigital number, since it uses as much as digits as its factorization.
11121233212157 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5040, while the sum is 32.
Adding to 11121233212157 its reverse (75121233212111), we get a palindrome (86242466424268).
The spelling of 11121233212157 in words is "eleven trillion, one hundred twenty-one billion, two hundred thirty-three million, two hundred twelve thousand, one hundred fifty-seven".
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