Base | Representation |
---|---|
bin | 10100101101110000… |
… | …11001001001110011 |
3 | 1001201001200120200002 |
4 | 22112320121021303 |
5 | 140234023100313 |
6 | 5035320020215 |
7 | 542411330255 |
oct | 122670311163 |
9 | 31631616602 |
10 | 11121300083 |
11 | 47977583a3 |
12 | 21a460166b |
13 | 10830b824a |
14 | 777047cd5 |
15 | 451550058 |
hex | 296e19273 |
11121300083 has 2 divisors, whose sum is σ = 11121300084. Its totient is φ = 11121300082.
The previous prime is 11121300007. The next prime is 11121300097. The reversal of 11121300083 is 38000312111.
11121300083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11121300083 - 212 = 11121295987 is a prime.
It is a super-2 number, since 2×111213000832 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (11121308083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560650041 + 5560650042.
It is an arithmetic number, because the mean of its divisors is an integer number (5560650042).
Almost surely, 211121300083 is an apocalyptic number.
11121300083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121300083 is an equidigital number, since it uses as much as digits as its factorization.
11121300083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 11121300083 its reverse (38000312111), we get a palindrome (49121612194).
The spelling of 11121300083 in words is "eleven billion, one hundred twenty-one million, three hundred thousand, eighty-three".
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