Base | Representation |
---|---|
bin | 10100101101110000… |
… | …11100010011101011 |
3 | 1001201001201020101121 |
4 | 22112320130103223 |
5 | 140234024004003 |
6 | 5035320200111 |
7 | 542411413033 |
oct | 122670342353 |
9 | 31631636347 |
10 | 11121313003 |
11 | 4797767079 |
12 | 21a4609037 |
13 | 10830c10a8 |
14 | 77704c8c3 |
15 | 451553cbd |
hex | 296e1c4eb |
11121313003 has 2 divisors, whose sum is σ = 11121313004. Its totient is φ = 11121313002.
The previous prime is 11121312953. The next prime is 11121313019. The reversal of 11121313003 is 30031312111.
It is an a-pointer prime, because the next prime (11121313019) can be obtained adding 11121313003 to its sum of digits (16).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11121313003 - 213 = 11121304811 is a prime.
It is not a weakly prime, because it can be changed into another prime (11121343003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560656501 + 5560656502.
It is an arithmetic number, because the mean of its divisors is an integer number (5560656502).
Almost surely, 211121313003 is an apocalyptic number.
11121313003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121313003 is an equidigital number, since it uses as much as digits as its factorization.
11121313003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11121313003 its reverse (30031312111), we get a palindrome (41152625114).
The spelling of 11121313003 in words is "eleven billion, one hundred twenty-one million, three hundred thirteen thousand, three".
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