Base | Representation |
---|---|
bin | 10100101101110001… |
… | …00011111100100101 |
3 | 1001201001202211022111 |
4 | 22112320203330211 |
5 | 140234031004133 |
6 | 5035321001021 |
7 | 542411603203 |
oct | 122670437445 |
9 | 31631684274 |
10 | 11121344293 |
11 | 4797788634 |
12 | 21a4623171 |
13 | 10831023c7 |
14 | 77705a073 |
15 | 45155d1cd |
hex | 296e23f25 |
11121344293 has 2 divisors, whose sum is σ = 11121344294. Its totient is φ = 11121344292.
The previous prime is 11121344287. The next prime is 11121344329. The reversal of 11121344293 is 39244312111.
Together with next prime (11121344329) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10180204609 + 941139684 = 100897^2 + 30678^2 .
It is an emirp because it is prime and its reverse (39244312111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11121344293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11121344263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560672146 + 5560672147.
It is an arithmetic number, because the mean of its divisors is an integer number (5560672147).
Almost surely, 211121344293 is an apocalyptic number.
It is an amenable number.
11121344293 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121344293 is an equidigital number, since it uses as much as digits as its factorization.
11121344293 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 31.
The spelling of 11121344293 in words is "eleven billion, one hundred twenty-one million, three hundred forty-four thousand, two hundred ninety-three".
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