Base | Representation |
---|---|
bin | 10000001011110000111… |
… | …110000000101101100001 |
3 | 10221022122020210200010022 |
4 | 100023300332000231201 |
5 | 121210132423200144 |
6 | 2210525001043225 |
7 | 143230654666625 |
oct | 20136076005541 |
9 | 3838566720108 |
10 | 1112144350049 |
11 | 399726545a27 |
12 | 15b65aa86515 |
13 | 80b4ab11115 |
14 | 3bb8433d185 |
15 | 1dde1c36cee |
hex | 102f0f80b61 |
1112144350049 has 2 divisors, whose sum is σ = 1112144350050. Its totient is φ = 1112144350048.
The previous prime is 1112144350019. The next prime is 1112144350091. The reversal of 1112144350049 is 9400534412111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 732491204449 + 379653145600 = 855857^2 + 616160^2 .
It is a cyclic number.
It is not a de Polignac number, because 1112144350049 - 220 = 1112143301473 is a prime.
It is not a weakly prime, because it can be changed into another prime (1112144350019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556072175024 + 556072175025.
It is an arithmetic number, because the mean of its divisors is an integer number (556072175025).
Almost surely, 21112144350049 is an apocalyptic number.
It is an amenable number.
1112144350049 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112144350049 is an equidigital number, since it uses as much as digits as its factorization.
1112144350049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 35.
The spelling of 1112144350049 in words is "one trillion, one hundred twelve billion, one hundred forty-four million, three hundred fifty thousand, forty-nine".
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