Base | Representation |
---|---|
bin | 10000001011110100010… |
… | …110001100001001111111 |
3 | 10221022210012102210201112 |
4 | 100023310112030021333 |
5 | 121210241430120111 |
6 | 2210534343432235 |
7 | 143232243454343 |
oct | 20136426141177 |
9 | 3838705383645 |
10 | 1112201020031 |
11 | 399755531a22 |
12 | 15b675a5567b |
13 | 80b5979345a |
14 | 3bb8ba91623 |
15 | 1dde6bcce8b |
hex | 102f458c27f |
1112201020031 has 2 divisors, whose sum is σ = 1112201020032. Its totient is φ = 1112201020030.
The previous prime is 1112201019989. The next prime is 1112201020037. The reversal of 1112201020031 is 1300201022111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1112201020031 - 214 = 1112201003647 is a prime.
It is a super-2 number, since 2×11122010200312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1112201019988 and 1112201020015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1112201020037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556100510015 + 556100510016.
It is an arithmetic number, because the mean of its divisors is an integer number (556100510016).
Almost surely, 21112201020031 is an apocalyptic number.
1112201020031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112201020031 is an equidigital number, since it uses as much as digits as its factorization.
1112201020031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1112201020031 its reverse (1300201022111), we get a palindrome (2412402042142).
The spelling of 1112201020031 in words is "one trillion, one hundred twelve billion, two hundred one million, twenty thousand, thirty-one".
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