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111220122011077 is a prime number
BaseRepresentation
bin11001010010011101110011…
…110111010100010111000101
3112120210112120112100222002001
4121102131303313110113011
5104034212302213323302
61032313452500545301
732266250206505122
oct3122356367242705
9476715515328061
10111220122011077
1132490209411002
12105832559b2231
134a0a0216131a1
141d67122a31749
15ccd155c1a787
hex652773dd45c5

111220122011077 has 2 divisors, whose sum is σ = 111220122011078. Its totient is φ = 111220122011076.

The previous prime is 111220122011057. The next prime is 111220122011129. The reversal of 111220122011077 is 770110221022111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76853959356321 + 34366162654756 = 8766639^2 + 5862266^2 .

It is an emirp because it is prime and its reverse (770110221022111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111220122011077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111220122011027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55610061005538 + 55610061005539.

It is an arithmetic number, because the mean of its divisors is an integer number (55610061005539).

Almost surely, 2111220122011077 is an apocalyptic number.

It is an amenable number.

111220122011077 is a deficient number, since it is larger than the sum of its proper divisors (1).

111220122011077 is an equidigital number, since it uses as much as digits as its factorization.

111220122011077 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 784, while the sum is 28.

Adding to 111220122011077 its reverse (770110221022111), we get a palindrome (881330343033188).

The spelling of 111220122011077 in words is "one hundred eleven trillion, two hundred twenty billion, one hundred twenty-two million, eleven thousand, seventy-seven".