Base | Representation |
---|---|
bin | 110011110010101001… |
… | …0011100100000000101 |
3 | 101122002011221012202121 |
4 | 1213211102130200011 |
5 | 3310240034001242 |
6 | 123032204005541 |
7 | 11015105621536 |
oct | 1474522344005 |
9 | 348064835677 |
10 | 111221000197 |
11 | 4319439a68a |
12 | 1967b8308b1 |
13 | a646464b28 |
14 | 555141c68d |
15 | 2d5e3d0667 |
hex | 19e549c805 |
111221000197 has 2 divisors, whose sum is σ = 111221000198. Its totient is φ = 111221000196.
The previous prime is 111221000183. The next prime is 111221000237. The reversal of 111221000197 is 791000122111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 92824418241 + 18396581956 = 304671^2 + 135634^2 .
It is a cyclic number.
It is not a de Polignac number, because 111221000197 - 211 = 111220998149 is a prime.
It is a super-2 number, since 2×1112210001972 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111221000147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55610500098 + 55610500099.
It is an arithmetic number, because the mean of its divisors is an integer number (55610500099).
Almost surely, 2111221000197 is an apocalyptic number.
It is an amenable number.
111221000197 is a deficient number, since it is larger than the sum of its proper divisors (1).
111221000197 is an equidigital number, since it uses as much as digits as its factorization.
111221000197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 25.
The spelling of 111221000197 in words is "one hundred eleven billion, two hundred twenty-one million, one hundred ninety-seven", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •