1112210011313 has 4 divisors (see below), whose sum is σ = 1112700622320. Its totient is φ = 1111719400308.

The previous prime is 1112210011189. The next prime is 1112210011351. The reversal of 1112210011313 is 3131100122111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1112210011313 is a prime.

It is a super-2 number, since 2×1112210011313² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1112210011291 and 1112210011300.

It is not an unprimeable number, because it can be changed into a prime (1112210011373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245302103 + ... + 245306636.

It is an arithmetic number, because the mean of its divisors is an integer number (278175155580).

Almost surely, 2^{1112210011313} is an apocalyptic number.

It is an amenable number.

1112210011313 is a deficient number, since it is larger than the sum of its proper divisors (490611007).

1112210011313 is an equidigital number, since it uses as much as digits as its factorization.

1112210011313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 490611006.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1112210011313 its reverse (3131100122111), we get a palindrome (4243310133424).

The spelling of 1112210011313 in words is "one trillion, one hundred twelve billion, two hundred ten million, eleven thousand, three hundred thirteen".