Base | Representation |
---|---|
bin | 1010000111011001000100… |
… | …0000010100100111100101 |
3 | 1110101021002111012100112011 |
4 | 2201312101000110213211 |
5 | 2424211031344010432 |
6 | 35353231300554221 |
7 | 2225355040405156 |
oct | 241662100244745 |
9 | 43337074170464 |
10 | 11122103110117 |
11 | 35a894828686a |
12 | 12b76559b2971 |
13 | 628a6b247a7c |
14 | 2a6453d3792d |
15 | 1444a10dd847 |
hex | a1d910149e5 |
11122103110117 has 2 divisors, whose sum is σ = 11122103110118. Its totient is φ = 11122103110116.
The previous prime is 11122103110103. The next prime is 11122103110141. The reversal of 11122103110117 is 71101130122111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5810963432836 + 5311139677281 = 2410594^2 + 2304591^2 .
It is a cyclic number.
It is not a de Polignac number, because 11122103110117 - 239 = 10572347296229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11122103110177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561051555058 + 5561051555059.
It is an arithmetic number, because the mean of its divisors is an integer number (5561051555059).
Almost surely, 211122103110117 is an apocalyptic number.
It is an amenable number.
11122103110117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11122103110117 is an equidigital number, since it uses as much as digits as its factorization.
11122103110117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 22.
Adding to 11122103110117 its reverse (71101130122111), we get a palindrome (82223233232228).
The spelling of 11122103110117 in words is "eleven trillion, one hundred twenty-two billion, one hundred three million, one hundred ten thousand, one hundred seventeen".
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