Base | Representation |
---|---|
bin | 110011110010101001… |
… | …1010010111011011011 |
3 | 101122002012100112120102 |
4 | 1213211103102323123 |
5 | 3310240113120011 |
6 | 123032212450015 |
7 | 11015110540514 |
oct | 1474523227333 |
9 | 348065315512 |
10 | 111221223131 |
11 | 43194532127 |
12 | 1967b91990b |
13 | a646512445 |
14 | 5551479a0b |
15 | 2d5e42673b |
hex | 19e54d2edb |
111221223131 has 2 divisors, whose sum is σ = 111221223132. Its totient is φ = 111221223130.
The previous prime is 111221223013. The next prime is 111221223133. The reversal of 111221223131 is 131322122111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111221223131 - 230 = 110147481307 is a prime.
It is a super-2 number, since 2×1112212231312 (a number of 23 digits) contains 22 as substring.
Together with 111221223133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (111221223133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55610611565 + 55610611566.
It is an arithmetic number, because the mean of its divisors is an integer number (55610611566).
Almost surely, 2111221223131 is an apocalyptic number.
111221223131 is a deficient number, since it is larger than the sum of its proper divisors (1).
111221223131 is an equidigital number, since it uses as much as digits as its factorization.
111221223131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 144, while the sum is 20.
Adding to 111221223131 its reverse (131322122111), we get a palindrome (242543345242).
The spelling of 111221223131 in words is "one hundred eleven billion, two hundred twenty-one million, two hundred twenty-three thousand, one hundred thirty-one".
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