11122133301133 has 4 divisors (see below), whose sum is σ = 11122208131840. Its totient is φ = 11122058470428.

The previous prime is 11122133301091. The next prime is 11122133301151. The reversal of 11122133301133 is 33110333122111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11122133301133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11122133301098 and 11122133301107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11122133301533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37191963 + ... + 37489816.

It is an arithmetic number, because the mean of its divisors is an integer number (2780552032960).

Almost surely, 2^{11122133301133} is an apocalyptic number.

It is an amenable number.

11122133301133 is a deficient number, since it is larger than the sum of its proper divisors (74830707).

11122133301133 is an equidigital number, since it uses as much as digits as its factorization.

11122133301133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 74830706.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11122133301133 its reverse (33110333122111), we get a palindrome (44232466423244).

The spelling of 11122133301133 in words is "eleven trillion, one hundred twenty-two billion, one hundred thirty-three million, three hundred one thousand, one hundred thirty-three".