Base | Representation |
---|---|
bin | 1010000111011001001100… |
… | …1101000110001100100111 |
3 | 1110101021012001122020020121 |
4 | 2201312103031012030213 |
5 | 2424211120320411401 |
6 | 35353235055542411 |
7 | 2225355666154603 |
oct | 241662315061447 |
9 | 43337161566217 |
10 | 11122140013351 |
11 | 35a89670a1804 |
12 | 12b766622aa07 |
13 | 628a75a98bc3 |
14 | 2a6458bc2503 |
15 | 1444a447cca1 |
hex | a1d93346327 |
11122140013351 has 2 divisors, whose sum is σ = 11122140013352. Its totient is φ = 11122140013350.
The previous prime is 11122140013307. The next prime is 11122140013399. The reversal of 11122140013351 is 15331004122111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11122140013351 - 211 = 11122140011303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11122140013301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561070006675 + 5561070006676.
It is an arithmetic number, because the mean of its divisors is an integer number (5561070006676).
Almost surely, 211122140013351 is an apocalyptic number.
11122140013351 is a deficient number, since it is larger than the sum of its proper divisors (1).
11122140013351 is an equidigital number, since it uses as much as digits as its factorization.
11122140013351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 11122140013351 its reverse (15331004122111), we get a palindrome (26453144135462).
The spelling of 11122140013351 in words is "eleven trillion, one hundred twenty-two billion, one hundred forty million, thirteen thousand, three hundred fifty-one".
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