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1112214111103 = 5130721677629
BaseRepresentation
bin10000001011110101001…
…000001000001101111111
310221022211010001220022001
4100023311020020031333
5121210303303023403
62210535532203131
7143232462646624
oct20136510101577
93838733056261
101112214111103
11399761963497
1215b67a3094a7
1380b5c3c7c54
143bb8d6dc34b
151dde7e16c1d
hex102f520837f

1112214111103 has 4 divisors (see below), whose sum is σ = 1112235840040. Its totient is φ = 1112192382168.

The previous prime is 1112214111097. The next prime is 1112214111131. The reversal of 1112214111103 is 3011114122111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1112214111103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1112214121103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10787508 + ... + 10890121.

It is an arithmetic number, because the mean of its divisors is an integer number (278058960010).

Almost surely, 21112214111103 is an apocalyptic number.

1112214111103 is a deficient number, since it is larger than the sum of its proper divisors (21728937).

1112214111103 is an equidigital number, since it uses as much as digits as its factorization.

1112214111103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21728936.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 1112214111103 its reverse (3011114122111), we get a palindrome (4123328233214).

The spelling of 1112214111103 in words is "one trillion, one hundred twelve billion, two hundred fourteen million, one hundred eleven thousand, one hundred three".

Divisors: 1 51307 21677629 1112214111103