Base | Representation |
---|---|
bin | 10000001011110101001… |
… | …000001000001101111111 |
3 | 10221022211010001220022001 |
4 | 100023311020020031333 |
5 | 121210303303023403 |
6 | 2210535532203131 |
7 | 143232462646624 |
oct | 20136510101577 |
9 | 3838733056261 |
10 | 1112214111103 |
11 | 399761963497 |
12 | 15b67a3094a7 |
13 | 80b5c3c7c54 |
14 | 3bb8d6dc34b |
15 | 1dde7e16c1d |
hex | 102f520837f |
1112214111103 has 4 divisors (see below), whose sum is σ = 1112235840040. Its totient is φ = 1112192382168.
The previous prime is 1112214111097. The next prime is 1112214111131. The reversal of 1112214111103 is 3011114122111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1112214111103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1112214121103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10787508 + ... + 10890121.
It is an arithmetic number, because the mean of its divisors is an integer number (278058960010).
Almost surely, 21112214111103 is an apocalyptic number.
1112214111103 is a deficient number, since it is larger than the sum of its proper divisors (21728937).
1112214111103 is an equidigital number, since it uses as much as digits as its factorization.
1112214111103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21728936.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 1112214111103 its reverse (3011114122111), we get a palindrome (4123328233214).
The spelling of 1112214111103 in words is "one trillion, one hundred twelve billion, two hundred fourteen million, one hundred eleven thousand, one hundred three".
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