Base | Representation |
---|---|
bin | 110011110010101011… |
… | …0101110011010010011 |
3 | 101122002021001012202201 |
4 | 1213211112232122103 |
5 | 3310240330402011 |
6 | 123032244024031 |
7 | 11015121303511 |
oct | 1474526563223 |
9 | 348067035681 |
10 | 111222122131 |
11 | 43194a965aa |
12 | 19680092017 |
13 | a6467686b3 |
14 | 55516314b1 |
15 | 2d5e552cc1 |
hex | 19e55ae693 |
111222122131 has 2 divisors, whose sum is σ = 111222122132. Its totient is φ = 111222122130.
The previous prime is 111222122129. The next prime is 111222122257. The reversal of 111222122131 is 131221222111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111222122131 - 21 = 111222122129 is a prime.
It is a super-2 number, since 2×1112221221312 (a number of 23 digits) contains 22 as substring.
Together with 111222122129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 111222122099 and 111222122108.
It is not a weakly prime, because it can be changed into another prime (111222122101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55611061065 + 55611061066.
It is an arithmetic number, because the mean of its divisors is an integer number (55611061066).
Almost surely, 2111222122131 is an apocalyptic number.
111222122131 is a deficient number, since it is larger than the sum of its proper divisors (1).
111222122131 is an equidigital number, since it uses as much as digits as its factorization.
111222122131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 96, while the sum is 19.
Adding to 111222122131 its reverse (131221222111), we get a palindrome (242443344242).
The spelling of 111222122131 in words is "one hundred eleven billion, two hundred twenty-two million, one hundred twenty-two thousand, one hundred thirty-one".
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