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11122344445673 is a prime number
BaseRepresentation
bin1010000111011001111101…
…1000111100011011101001
31110101021201022022110200002
42201312133120330123221
52424212030134230143
635353311241352345
72225364030622316
oct241663730743351
943337638273602
1011122344445673
1135a8a6153183a
1212b77027986b5
13628aa9245786
142a6477dd9d0d
151444b73b05b8
hexa1d9f63c6e9

11122344445673 has 2 divisors, whose sum is σ = 11122344445674. Its totient is φ = 11122344445672.

The previous prime is 11122344445637. The next prime is 11122344445691. The reversal of 11122344445673 is 37654444322111.

It is a happy number.

Together with previous prime (11122344445637) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8338395466384 + 2783948979289 = 2887628^2 + 1668517^2 .

It is a cyclic number.

It is not a de Polignac number, because 11122344445673 - 226 = 11122277336809 is a prime.

It is not a weakly prime, because it can be changed into another prime (11122344445273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561172222836 + 5561172222837.

It is an arithmetic number, because the mean of its divisors is an integer number (5561172222837).

Almost surely, 211122344445673 is an apocalyptic number.

It is an amenable number.

11122344445673 is a deficient number, since it is larger than the sum of its proper divisors (1).

11122344445673 is an equidigital number, since it uses as much as digits as its factorization.

11122344445673 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1935360, while the sum is 47.

Adding to 11122344445673 its reverse (37654444322111), we get a palindrome (48776788767784).

The spelling of 11122344445673 in words is "eleven trillion, one hundred twenty-two billion, three hundred forty-four million, four hundred forty-five thousand, six hundred seventy-three".