Search a number
-
+
111224201212121 is a prime number
BaseRepresentation
bin11001010010100001100111…
…000000001111000011011001
3112120210221002211002211221012
4121102201213000033003121
5104034244131002241441
61032315405340223305
732266453251236414
oct3122414700170331
9476727084084835
10111224201212121
1132491a11a80138
1210583bb3b3ab35
134a0a52177540a
141d673cc6c0b7b
15ccd2e3dd79eb
hex65286700f0d9

111224201212121 has 2 divisors, whose sum is σ = 111224201212122. Its totient is φ = 111224201212120.

The previous prime is 111224201212013. The next prime is 111224201212139. The reversal of 111224201212121 is 121212102422111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86946300250000 + 24277900962121 = 9324500^2 + 4927261^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111224201212121 is a prime.

It is not a weakly prime, because it can be changed into another prime (111224201212141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55612100606060 + 55612100606061.

It is an arithmetic number, because the mean of its divisors is an integer number (55612100606061).

Almost surely, 2111224201212121 is an apocalyptic number.

It is an amenable number.

111224201212121 is a deficient number, since it is larger than the sum of its proper divisors (1).

111224201212121 is an equidigital number, since it uses as much as digits as its factorization.

111224201212121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 256, while the sum is 23.

Adding to 111224201212121 its reverse (121212102422111), we get a palindrome (232436303634232).

The spelling of 111224201212121 in words is "one hundred eleven trillion, two hundred twenty-four billion, two hundred one million, two hundred twelve thousand, one hundred twenty-one".