111230211433 has 4 divisors (see below), whose sum is σ = 121342048848. Its totient is φ = 101118374020.

The previous prime is 111230211431. The next prime is 111230211451. The reversal of 111230211433 is 334112032111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111230211433 - 2¹ = 111230211431 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111230211431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5055918691 + ... + 5055918712.

It is an arithmetic number, because the mean of its divisors is an integer number (30335512212).

Almost surely, 2^111230211433 is an apocalyptic number.

It is an amenable number.

111230211433 is a deficient number, since it is larger than the sum of its proper divisors (10111837415).

111230211433 is a wasteful number, since it uses less digits than its factorization.

111230211433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10111837414.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 111230211433 its reverse (334112032111), we get a palindrome (445342243544).

The spelling of 111230211433 in words is "one hundred eleven billion, two hundred thirty million, two hundred eleven thousand, four hundred thirty-three".