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11123102013103 is a prime number
BaseRepresentation
bin1010000111011100110010…
…0010110101011010101111
31110101100200002210212211001
42201313030202311122233
52424220103103404403
635353514342541131
72225421560056603
oct241671442653257
943340602725731
1011123102013103
1135a9310120423
1212b78944377a7
13628b9a18c822
142a650a87b503
1514450db54c1d
hexa1dcc8b56af

11123102013103 has 2 divisors, whose sum is σ = 11123102013104. Its totient is φ = 11123102013102.

The previous prime is 11123102013029. The next prime is 11123102013151. The reversal of 11123102013103 is 30131020132111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11123102013103 is a prime.

It is a super-2 number, since 2×111231020131032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11123102013403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561551006551 + 5561551006552.

It is an arithmetic number, because the mean of its divisors is an integer number (5561551006552).

Almost surely, 211123102013103 is an apocalyptic number.

11123102013103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11123102013103 is an equidigital number, since it uses as much as digits as its factorization.

11123102013103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 11123102013103 its reverse (30131020132111), we get a palindrome (41254122145214).

The spelling of 11123102013103 in words is "eleven trillion, one hundred twenty-three billion, one hundred two million, thirteen thousand, one hundred three".