Base | Representation |
---|---|
bin | 10000001011111100001… |
… | …110001010000000110111 |
3 | 10221100010102000210001011 |
4 | 100023330032022000313 |
5 | 121211024240204311 |
6 | 2210555423213051 |
7 | 143235436422055 |
oct | 20137416120067 |
9 | 3840112023034 |
10 | 1112333131831 |
11 | 399813066529 |
12 | 15b6b2147187 |
13 | 80b7ac6b20c |
14 | 3bba14411d5 |
15 | 1de035c7321 |
hex | 102fc38a037 |
1112333131831 has 2 divisors, whose sum is σ = 1112333131832. Its totient is φ = 1112333131830.
The previous prime is 1112333131783. The next prime is 1112333131841. The reversal of 1112333131831 is 1381313332111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1112333131831 - 219 = 1112332607543 is a prime.
It is a super-2 number, since 2×11123331318312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1112333131793 and 1112333131802.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1112333131841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556166565915 + 556166565916.
It is an arithmetic number, because the mean of its divisors is an integer number (556166565916).
Almost surely, 21112333131831 is an apocalyptic number.
1112333131831 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112333131831 is an equidigital number, since it uses as much as digits as its factorization.
1112333131831 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3888, while the sum is 31.
Adding to 1112333131831 its reverse (1381313332111), we get a palindrome (2493646463942).
The spelling of 1112333131831 in words is "one trillion, one hundred twelve billion, three hundred thirty-three million, one hundred thirty-one thousand, eight hundred thirty-one".
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