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1112394107633 is a prime number
BaseRepresentation
bin10000001011111111110…
…110110000101011110001
310221100021122202200010012
4100023333312300223301
5121211140342421013
62211005442144305
7143240106622064
oct20137766605361
93840248680105
101112394107633
11399844523556
1215b70a652095
1380b8a79a383
143bba95948db
151de08b1e1a8
hex102ffdb0af1

1112394107633 has 2 divisors, whose sum is σ = 1112394107634. Its totient is φ = 1112394107632.

The previous prime is 1112394107599. The next prime is 1112394107647. The reversal of 1112394107633 is 3367014932111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1014417595489 + 97976512144 = 1007183^2 + 313012^2 .

It is a cyclic number.

It is not a de Polignac number, because 1112394107633 - 222 = 1112389913329 is a prime.

It is not a weakly prime, because it can be changed into another prime (1112394107333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556197053816 + 556197053817.

It is an arithmetic number, because the mean of its divisors is an integer number (556197053817).

Almost surely, 21112394107633 is an apocalyptic number.

It is an amenable number.

1112394107633 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112394107633 is an equidigital number, since it uses as much as digits as its factorization.

1112394107633 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81648, while the sum is 41.

The spelling of 1112394107633 in words is "one trillion, one hundred twelve billion, three hundred ninety-four million, one hundred seven thousand, six hundred thirty-three".