Base | Representation |
---|---|
bin | 10000001011111111110… |
… | …110110000101011110001 |
3 | 10221100021122202200010012 |
4 | 100023333312300223301 |
5 | 121211140342421013 |
6 | 2211005442144305 |
7 | 143240106622064 |
oct | 20137766605361 |
9 | 3840248680105 |
10 | 1112394107633 |
11 | 399844523556 |
12 | 15b70a652095 |
13 | 80b8a79a383 |
14 | 3bba95948db |
15 | 1de08b1e1a8 |
hex | 102ffdb0af1 |
1112394107633 has 2 divisors, whose sum is σ = 1112394107634. Its totient is φ = 1112394107632.
The previous prime is 1112394107599. The next prime is 1112394107647. The reversal of 1112394107633 is 3367014932111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1014417595489 + 97976512144 = 1007183^2 + 313012^2 .
It is a cyclic number.
It is not a de Polignac number, because 1112394107633 - 222 = 1112389913329 is a prime.
It is not a weakly prime, because it can be changed into another prime (1112394107333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556197053816 + 556197053817.
It is an arithmetic number, because the mean of its divisors is an integer number (556197053817).
Almost surely, 21112394107633 is an apocalyptic number.
It is an amenable number.
1112394107633 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112394107633 is an equidigital number, since it uses as much as digits as its factorization.
1112394107633 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81648, while the sum is 41.
The spelling of 1112394107633 in words is "one trillion, one hundred twelve billion, three hundred ninety-four million, one hundred seven thousand, six hundred thirty-three".
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