Base | Representation |
---|---|
bin | 10100101110000110… |
… | …01111100011001011 |
3 | 1001201021001002020121 |
4 | 22113003033203023 |
5 | 140240240104311 |
6 | 5035501004111 |
7 | 542444444446 |
oct | 122703174313 |
9 | 31637032217 |
10 | 11124144331 |
11 | 4799320313 |
12 | 21a5553637 |
13 | 1083872a31 |
14 | 77758865d |
15 | 451912b71 |
hex | 2970cf8cb |
11124144331 has 2 divisors, whose sum is σ = 11124144332. Its totient is φ = 11124144330.
The previous prime is 11124144329. The next prime is 11124144337. The reversal of 11124144331 is 13344142111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11124144331 - 21 = 11124144329 is a prime.
It is a super-2 number, since 2×111241443312 (a number of 21 digits) contains 22 as substring.
Together with 11124144329, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 11124144296 and 11124144305.
It is not a weakly prime, because it can be changed into another prime (11124144337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5562072165 + 5562072166.
It is an arithmetic number, because the mean of its divisors is an integer number (5562072166).
Almost surely, 211124144331 is an apocalyptic number.
11124144331 is a deficient number, since it is larger than the sum of its proper divisors (1).
11124144331 is an equidigital number, since it uses as much as digits as its factorization.
11124144331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1152, while the sum is 25.
Adding to 11124144331 its reverse (13344142111), we get a palindrome (24468286442).
The spelling of 11124144331 in words is "eleven billion, one hundred twenty-four million, one hundred forty-four thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •