Base | Representation |
---|---|
bin | 1010000111100000111101… |
… | …1000110000010011101111 |
3 | 1110101110120020222111002101 |
4 | 2201320033120300103233 |
5 | 2424224402200203312 |
6 | 35354221523035531 |
7 | 2225461425062206 |
oct | 241701730602357 |
9 | 43343506874071 |
10 | 11124223444207 |
11 | 35a9836143195 |
12 | 12b7b47b0bba7 |
13 | 629018605123 |
14 | 2a65b579823d |
15 | 144577320a57 |
hex | a1e0f6304ef |
11124223444207 has 2 divisors, whose sum is σ = 11124223444208. Its totient is φ = 11124223444206.
The previous prime is 11124223444181. The next prime is 11124223444211. The reversal of 11124223444207 is 70244432242111.
11124223444207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11124223444207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11124223444247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5562111722103 + 5562111722104.
It is an arithmetic number, because the mean of its divisors is an integer number (5562111722104).
Almost surely, 211124223444207 is an apocalyptic number.
11124223444207 is a deficient number, since it is larger than the sum of its proper divisors (1).
11124223444207 is an equidigital number, since it uses as much as digits as its factorization.
11124223444207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86016, while the sum is 37.
Adding to 11124223444207 its reverse (70244432242111), we get a palindrome (81368655686318).
The spelling of 11124223444207 in words is "eleven trillion, one hundred twenty-four billion, two hundred twenty-three million, four hundred forty-four thousand, two hundred seven".
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