Base | Representation |
---|---|
bin | 110011110011010011… |
… | …0111010101101011111 |
3 | 101122010201121020101121 |
4 | 1213212212322231133 |
5 | 3310311221102111 |
6 | 123034314351411 |
7 | 11015465060035 |
oct | 1474646725537 |
9 | 348121536347 |
10 | 111243144031 |
11 | 431a5944678 |
12 | 1968712b567 |
13 | a64ac18ca6 |
14 | 5554344555 |
15 | 2d61306871 |
hex | 19e69bab5f |
111243144031 has 2 divisors, whose sum is σ = 111243144032. Its totient is φ = 111243144030.
The previous prime is 111243143993. The next prime is 111243144043. The reversal of 111243144031 is 130441342111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111243144031 - 211 = 111243141983 is a prime.
It is a super-2 number, since 2×1112431440312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111243143987 and 111243144005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111243144731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55621572015 + 55621572016.
It is an arithmetic number, because the mean of its divisors is an integer number (55621572016).
Almost surely, 2111243144031 is an apocalyptic number.
111243144031 is a deficient number, since it is larger than the sum of its proper divisors (1).
111243144031 is an equidigital number, since it uses as much as digits as its factorization.
111243144031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 111243144031 its reverse (130441342111), we get a palindrome (241684486142).
The spelling of 111243144031 in words is "one hundred eleven billion, two hundred forty-three million, one hundred forty-four thousand, thirty-one".
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