Base | Representation |
---|---|
bin | 110011110011010011… |
… | …1001101100101001011 |
3 | 101122010201202011102021 |
4 | 1213212213031211023 |
5 | 3310311231040243 |
6 | 123034320145311 |
7 | 11015465531263 |
oct | 1474647154513 |
9 | 348121664367 |
10 | 111243221323 |
11 | 431a5997753 |
12 | 19687168237 |
13 | a64ac45220 |
14 | 55543647a3 |
15 | 2d6131e6ed |
hex | 19e69cd94b |
111243221323 has 4 divisors (see below), whose sum is σ = 119800392208. Its totient is φ = 102686050440.
The previous prime is 111243221291. The next prime is 111243221359. The reversal of 111243221323 is 323122342111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 111243221323 - 25 = 111243221291 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (111243221363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4278585423 + ... + 4278585448.
It is an arithmetic number, because the mean of its divisors is an integer number (29950098052).
Almost surely, 2111243221323 is an apocalyptic number.
111243221323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
111243221323 is a deficient number, since it is larger than the sum of its proper divisors (8557170885).
111243221323 is an equidigital number, since it uses as much as digits as its factorization.
111243221323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8557170884.
The product of its digits is 1728, while the sum is 25.
Adding to 111243221323 its reverse (323122342111), we get a palindrome (434365563434).
The spelling of 111243221323 in words is "one hundred eleven billion, two hundred forty-three million, two hundred twenty-one thousand, three hundred twenty-three".
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