11124331331 has 4 divisors (see below), whose sum is σ = 11139804000. Its totient is φ = 11108858664.

The previous prime is 11124331321. The next prime is 11124331367. The reversal of 11124331331 is 13313342111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11124331331 is a prime.

It is a super-2 number, since 2×11124331331² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11124331297 and 11124331306.

It is not an unprimeable number, because it can be changed into a prime (11124331321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7735256 + ... + 7736693.

It is an arithmetic number, because the mean of its divisors is an integer number (2784951000).

Almost surely, 2^11124331331 is an apocalyptic number.

11124331331 is a deficient number, since it is larger than the sum of its proper divisors (15472669).

11124331331 is an equidigital number, since it uses as much as digits as its factorization.

11124331331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15472668.

The product of its digits is 648, while the sum is 23.

Adding to 11124331331 its reverse (13313342111), we get a palindrome (24437673442).

The spelling of 11124331331 in words is "eleven billion, one hundred twenty-four million, three hundred thirty-one thousand, three hundred thirty-one".