1112433333133 has 4 divisors (see below), whose sum is σ = 1138303875808. Its totient is φ = 1086562790460.

The previous prime is 1112433333107. The next prime is 1112433333191. The reversal of 1112433333133 is 3313333342111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1112433333133 - 2³⁷ = 974994379661 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1112433333095 and 1112433333104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1112433330133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12935271273 + ... + 12935271358.

It is an arithmetic number, because the mean of its divisors is an integer number (284575968952).

Almost surely, 2^{1112433333133} is an apocalyptic number.

It is an amenable number.

1112433333133 is a deficient number, since it is larger than the sum of its proper divisors (25870542675).

1112433333133 is an equidigital number, since it uses as much as digits as its factorization.

1112433333133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25870542674.

The product of its digits is 17496, while the sum is 31.

Adding to 1112433333133 its reverse (3313333342111), we get a palindrome (4425766675244).

The spelling of 1112433333133 in words is "one trillion, one hundred twelve billion, four hundred thirty-three million, three hundred thirty-three thousand, one hundred thirty-three".