111243413401 has 2 divisors, whose sum is σ = 111243413402. Its totient is φ = 111243413400.

The previous prime is 111243413389. The next prime is 111243413509. The reversal of 111243413401 is 104314342111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75768067600 + 35475345801 = 275260^2 + 188349^2 .

It is a cyclic number.

It is not a de Polignac number, because 111243413401 - 2¹³ = 111243405209 is a prime.

It is not a weakly prime, because it can be changed into another prime (111243413201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55621706700 + 55621706701.

It is an arithmetic number, because the mean of its divisors is an integer number (55621706701).

Almost surely, 2^111243413401 is an apocalyptic number.

It is an amenable number.

111243413401 is a deficient number, since it is larger than the sum of its proper divisors (1).

111243413401 is an equidigital number, since it uses as much as digits as its factorization.

111243413401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 111243413401 its reverse (104314342111), we get a palindrome (215557755512).

The spelling of 111243413401 in words is "one hundred eleven billion, two hundred forty-three million, four hundred thirteen thousand, four hundred one".