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11125213537 = 29478162299
BaseRepresentation
bin10100101110001110…
…10100100101100001
31001201100001101220211
422113013110211201
5140241023313122
65035535534121
7542456516614
oct122707244541
931640041824
1011125213537
114799990659
1221a598a341
131083b585b9
1477778617b
15451a74877
hex2971d4961

11125213537 has 8 divisors (see below), whose sum is σ = 11753712000. Its totient is φ = 10513039824.

The previous prime is 11125213523. The next prime is 11125213543. The reversal of 11125213537 is 73531252111.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11125213537 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11125213499 and 11125213508.

It is not an unprimeable number, because it can be changed into a prime (11125213037) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4079787 + ... + 4082512.

It is an arithmetic number, because the mean of its divisors is an integer number (1469214000).

Almost surely, 211125213537 is an apocalyptic number.

It is an amenable number.

11125213537 is a deficient number, since it is larger than the sum of its proper divisors (628498463).

11125213537 is an equidigital number, since it uses as much as digits as its factorization.

11125213537 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8162375.

The product of its digits is 6300, while the sum is 31.

Adding to 11125213537 its reverse (73531252111), we get a palindrome (84656465648).

The spelling of 11125213537 in words is "eleven billion, one hundred twenty-five million, two hundred thirteen thousand, five hundred thirty-seven".

Divisors: 1 29 47 1363 8162299 236706671 383628053 11125213537