Base | Representation |
---|---|
bin | 1010000111101000000111… |
… | …1001000011000001111111 |
3 | 1110101122112010210211212002 |
4 | 2201322001321003001333 |
5 | 2424242320443342002 |
6 | 35355140310132515 |
7 | 2225560142636261 |
oct | 241720171030177 |
9 | 43348463724762 |
10 | 11126144512127 |
11 | 35aa631578a27 |
12 | 12b83a335113b |
13 | 6292636041c8 |
14 | 2a6718987b31 |
15 | 14463ace1002 |
hex | a1e81e4307f |
11126144512127 has 2 divisors, whose sum is σ = 11126144512128. Its totient is φ = 11126144512126.
The previous prime is 11126144512079. The next prime is 11126144512151. The reversal of 11126144512127 is 72121544162111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11126144512127 - 210 = 11126144511103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11126147512127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5563072256063 + 5563072256064.
It is an arithmetic number, because the mean of its divisors is an integer number (5563072256064).
Almost surely, 211126144512127 is an apocalyptic number.
11126144512127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11126144512127 is an equidigital number, since it uses as much as digits as its factorization.
11126144512127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 26880, while the sum is 38.
Adding to 11126144512127 its reverse (72121544162111), we get a palindrome (83247688674238).
The spelling of 11126144512127 in words is "eleven trillion, one hundred twenty-six billion, one hundred forty-four million, five hundred twelve thousand, one hundred twenty-seven".
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