Base | Representation |
---|---|
bin | 10100101110011100… |
… | …01000101111001101 |
3 | 1001201110102011111121 |
4 | 22113032020233031 |
5 | 140242003000023 |
6 | 5040042120541 |
7 | 542510640163 |
oct | 122716105715 |
9 | 31643364447 |
10 | 11127000013 |
11 | 479a9a0888 |
12 | 21a64b0151 |
13 | 108433279c |
14 | 777acd233 |
15 | 451cc8d5d |
hex | 297388bcd |
11127000013 has 2 divisors, whose sum is σ = 11127000014. Its totient is φ = 11127000012.
The previous prime is 11126999999. The next prime is 11127000043. The reversal of 11127000013 is 31000072111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11034031849 + 92968164 = 105043^2 + 9642^2 .
It is an emirp because it is prime and its reverse (31000072111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11127000013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11127000043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5563500006 + 5563500007.
It is an arithmetic number, because the mean of its divisors is an integer number (5563500007).
Almost surely, 211127000013 is an apocalyptic number.
It is an amenable number.
11127000013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11127000013 is an equidigital number, since it uses as much as digits as its factorization.
11127000013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 16.
Adding to 11127000013 its reverse (31000072111), we get a palindrome (42127072124).
The spelling of 11127000013 in words is "eleven billion, one hundred twenty-seven million, thirteen", and thus it is an aban number.
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