Search a number
-
+
11130000020177 is a prime number
BaseRepresentation
bin1010000111110110011110…
…1100101001001011010001
31110102000110211121221121112
42201331213230221023101
52424323220001121202
635401015035103105
72226054530133443
oct241754754511321
943360424557545
1011130000020177
11360122a942215
1212b909a5a1a95
13629729304b0c
142a69a2a48493
151447b4523b52
hexa1f67b292d1

11130000020177 has 2 divisors, whose sum is σ = 11130000020178. Its totient is φ = 11130000020176.

The previous prime is 11130000020081. The next prime is 11130000020203. The reversal of 11130000020177 is 77102000003111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10034982182416 + 1095017837761 = 3167804^2 + 1046431^2 .

It is a cyclic number.

It is not a de Polignac number, because 11130000020177 - 212 = 11130000016081 is a prime.

It is a super-2 number, since 2×111300000201772 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11130000020077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565000010088 + 5565000010089.

It is an arithmetic number, because the mean of its divisors is an integer number (5565000010089).

Almost surely, 211130000020177 is an apocalyptic number.

It is an amenable number.

11130000020177 is a deficient number, since it is larger than the sum of its proper divisors (1).

11130000020177 is an equidigital number, since it uses as much as digits as its factorization.

11130000020177 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 294, while the sum is 23.

Adding to 11130000020177 its reverse (77102000003111), we get a palindrome (88232000023288).

The spelling of 11130000020177 in words is "eleven trillion, one hundred thirty billion, twenty thousand, one hundred seventy-seven".