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11130000103 = 29755950773
BaseRepresentation
bin10100101110110011…
…00101001011100111
31001201200001120212001
422113121211023213
5140243240000403
65040230310131
7542545303615
oct122731451347
931650046761
1011130000103
1147a165a8a2
1221a74b8347
131084b431a1
147782706b5
154521bcc1d
hex2976652e7

11130000103 has 8 divisors (see below), whose sum is σ = 11515543200. Its totient is φ = 10744573728.

The previous prime is 11130000047. The next prime is 11130000157. The reversal of 11130000103 is 30100003111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11130000103 - 213 = 11129991911 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11130000103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11130000163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 193825 + ... + 244597.

It is an arithmetic number, because the mean of its divisors is an integer number (1439442900).

Almost surely, 211130000103 is an apocalyptic number.

11130000103 is a deficient number, since it is larger than the sum of its proper divisors (385543097).

11130000103 is an equidigital number, since it uses as much as digits as its factorization.

11130000103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58361.

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 11130000103 its reverse (30100003111), we get a palindrome (41230003214).

The spelling of 11130000103 in words is "eleven billion, one hundred thirty million, one hundred three", and thus it is an aban number.

Divisors: 1 29 7559 50773 219211 1472417 383793107 11130000103