111300113131 has 2 divisors, whose sum is σ = 111300113132. Its totient is φ = 111300113130.

The previous prime is 111300113107. The next prime is 111300113147. The reversal of 111300113131 is 131311003111.

It is an a-pointer prime, because the next prime (111300113147) can be obtained adding 111300113131 to its sum of digits (16).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111300113131 - 2⁹ = 111300112619 is a prime.

It is a super-2 number, since 2×111300113131² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (111300113101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55650056565 + 55650056566.

It is an arithmetic number, because the mean of its divisors is an integer number (55650056566).

Almost surely, 2^111300113131 is an apocalyptic number.

111300113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

111300113131 is an equidigital number, since it uses as much as digits as its factorization.

111300113131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 111300113131 its reverse (131311003111), we get a palindrome (242611116242).

The spelling of 111300113131 in words is "one hundred eleven billion, three hundred million, one hundred thirteen thousand, one hundred thirty-one".