Base | Representation |
---|---|
bin | 10000001100100100000… |
… | …011100001101110011011 |
3 | 10221101211222120001021202 |
4 | 100030210003201232123 |
5 | 121213411331342021 |
6 | 2211150015224415 |
7 | 143261133043655 |
oct | 20144403415633 |
9 | 3841758501252 |
10 | 1113001434011 |
11 | 39a026325885 |
12 | 15b859b1810b |
13 | 80c5655c8ac |
14 | 3bc260c76d5 |
15 | 1de420d7a0b |
hex | 103240e1b9b |
1113001434011 has 2 divisors, whose sum is σ = 1113001434012. Its totient is φ = 1113001434010.
The previous prime is 1113001434007. The next prime is 1113001434029. The reversal of 1113001434011 is 1104341003111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1113001434011 - 22 = 1113001434007 is a prime.
It is a super-2 number, since 2×11130014340112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1113001434071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556500717005 + 556500717006.
It is an arithmetic number, because the mean of its divisors is an integer number (556500717006).
Almost surely, 21113001434011 is an apocalyptic number.
1113001434011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113001434011 is an equidigital number, since it uses as much as digits as its factorization.
1113001434011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1113001434011 its reverse (1104341003111), we get a palindrome (2217342437122).
The spelling of 1113001434011 in words is "one trillion, one hundred thirteen billion, one million, four hundred thirty-four thousand, eleven".
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