111300230011 has 4 divisors (see below), whose sum is σ = 111983053672. Its totient is φ = 110617406352.

The previous prime is 111300229993. The next prime is 111300230023. The reversal of 111300230011 is 110032003111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110032003111 = 46171 ⋅2383141.

It is a cyclic number.

It is not a de Polignac number, because 111300230011 - 2²¹ = 111298132859 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111300229973 and 111300230000.

It is not an unprimeable number, because it can be changed into a prime (111300230071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 341411586 + ... + 341411911.

It is an arithmetic number, because the mean of its divisors is an integer number (27995763418).

Almost surely, 2^111300230011 is an apocalyptic number.

111300230011 is a deficient number, since it is larger than the sum of its proper divisors (682823661).

111300230011 is an equidigital number, since it uses as much as digits as its factorization.

111300230011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 682823660.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 111300230011 its reverse (110032003111), we get a palindrome (221332233122).

The spelling of 111300230011 in words is "one hundred eleven billion, three hundred million, two hundred thirty thousand, eleven".