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111300230117 is a prime number
BaseRepresentation
bin110011110101000000…
…0101011101111100101
3101122021201000111210002
41213222000223233211
53310420324330432
6123044114111045
711020060226546
oct1475200535745
9348251014702
10111300230117
114322509525a
12196a227b485
13a6599b583b
14555bb644cd
152d66330e62
hex19ea02bbe5

111300230117 has 2 divisors, whose sum is σ = 111300230118. Its totient is φ = 111300230116.

The previous prime is 111300230113. The next prime is 111300230123. The reversal of 111300230117 is 711032003111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101073762241 + 10226467876 = 317921^2 + 101126^2 .

It is an emirp because it is prime and its reverse (711032003111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111300230117 - 22 = 111300230113 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111300230113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55650115058 + 55650115059.

It is an arithmetic number, because the mean of its divisors is an integer number (55650115059).

Almost surely, 2111300230117 is an apocalyptic number.

It is an amenable number.

111300230117 is a deficient number, since it is larger than the sum of its proper divisors (1).

111300230117 is an equidigital number, since it uses as much as digits as its factorization.

111300230117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126, while the sum is 20.

Adding to 111300230117 its reverse (711032003111), we get a palindrome (822332233228).

The spelling of 111300230117 in words is "one hundred eleven billion, three hundred million, two hundred thirty thousand, one hundred seventeen".