11130030000441 has 36 divisors (see below), whose sum is σ = 17955580430736. Its totient is φ = 6588601160400.

The previous prime is 11130030000437. The next prime is 11130030000449. The reversal of 11130030000441 is 14400003003111.

11130030000441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11130030000441 - 2² = 11130030000437 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11130030000449) by changing a digit.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 30218395 + ... + 30584496.

It is an arithmetic number, because the mean of its divisors is an integer number (498766123076).

Almost surely, 2^{11130030000441} is an apocalyptic number.

11130030000441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

11130030000441 is a deficient number, since it is larger than the sum of its proper divisors (6825550430295).

11130030000441 is a wasteful number, since it uses less digits than its factorization.

11130030000441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60802994 (or 60802948 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 11130030000441 its reverse (14400003003111), we get a palindrome (25530033003552).

The spelling of 11130030000441 in words is "eleven trillion, one hundred thirty billion, thirty million, four hundred forty-one", and thus it is an aban number.